Question

194

Jquery drop-down menu: how to each() for each item

rated 0 times [ 195] [ 1] / answers: 1 / hits: 9323 / 10 Years ago, wed, march 26, 2014, 12:00:00

I need to run a function for each item in a drop down menu. The code is:

    $( document ).ready(function() {

     $('[id*=lwayer_x002d_EisDikigoros_1eef9a23-7a35-4dcf-8de9-a088b4681b2b]')

            .each(function(index) {

/* here, I need to do some manipulation on the item */

                  console.log(index is:+???+value is+???);

            });



    });

I understand that i need to put something before each() to select all items but I don't know what to put

Thank you

The drop down menu is :

<select id=lwayer_x002d_EisDikigoros_1eef9a23-7a35-4dcf-8de9-a088b4681b2b_$LookupField title=Εισ. Δικηγόρος/οι>

<option value=0>(None)</option> <option value=1>(Name1)</option>  etc

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3 Years ago

answered 10 Years ago rickjordond · Accepted Answer

Try this:

$(document).ready(function(){

    $('select[id*=lwayer_x002d_EisDikigoros_1eef9a23-7a35-4dcf-8de9-a088b4681b2b] option').each(function(index,value) {

        console.log(index is:+index); // index

        console.log(value is+$(this).val()); // dropdown option value

        console.log(dropdown text value is+$(this).text()); //dropdown option text

    });

});

DEMO