Question

114

promise.then() returns Promise { < pending> }

rated 0 times [ 121] [ 7] / answers: 1 / hits: 20889 / 3 Years ago, sat, january 16, 2021, 12:00:00

Function fetchData returns a promise and then I'm dealing with that promise in generateURL function by chaining the promise with .then however it returns Promise < pending >. Function generateURL should return a string What am I doing wrong?

const fetch = require('node-fetch');



const fetchData = async () => {

  return await fetch('https://jsonplaceholder.typicode.com/todos/1');

};



const generateURL = () => {

  const baseURL = 'https://cdn.test.com/';

  fetchData().then((res) => {

    const data = res.json();

    console.log('data', data);

    const id = data.id;

    console.log('id', id);

    const generatedURL = `${baseURL}${id}`;

    return generatedURL;

  });

};

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editha

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2 Years ago

answered 4 Years ago josh · Accepted Answer

Reduced your code by a bit instead of adding multiple promise resolution

  const fetch = require('node-fetch');



const everything = async () =>{

    const response = await fetch('https://jsonplaceholder.typicode.com/todos/1');

    const {id} = await response.json();

    return `https://cdn.test.com/${id}`

}

everything().then((res)=>console.log(res));