Question

8

Find the biggest number in an array by using JavaScript loops

rated 0 times [ 11] [ 3] / answers: 1 / hits: 34304 / 5 Years ago, mon, february 11, 2019, 12:00:00

Create a function called biggestNumberInArray().

That takes an array as a parameter and returns the biggest number.

Here is an array

const array = [-1, 0, 3, 100, 99, 2, 99]

What I try in my JavaScript code:

 function biggestNumberInArray(arr) {

   for (let i = 0; i < array.length; i++) {

      for(let j=1;j<array.length;j++){

          for(let k =2;k<array.length;k++){

              if(array[i]>array[j] && array[i]>array[k]){

                    console.log(array[i]);

           }

         }

      }

   }

}

It returns 3 100 99.

I want to return just 100 because it is the biggest number.

Is there a better way to use loops to get the biggest value?

Using three different JavaScript loops to achieve this (for, forEach, for of, for in).

You can use three of them to accomplish it.

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breanab

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3 Years ago

answered 5 Years ago morrismilom · Accepted Answer

zer00ne's answer should be better for simplicity, but if you still want to follow the for-loop way, here it is:

function biggestNumberInArray (arr) {

    // The largest number at first should be the first element or null for empty array

    var largest = arr[0] || null;



    // Current number, handled by the loop

    var number = null;

    for (var i = 0; i < arr.length; i++) {

        // Update current number

        number = arr[i];



        // Compares stored largest number with current number, stores the largest one

        largest = Math.max(largest, number);

    }



    return largest;

}