Question

125

Array.includes() to find object in array

rated 0 times [ 126] [ 1] / answers: 1 / hits: 99313 / 6 Years ago, mon, july 30, 2018, 12:00:00

I'm attempting to find an object in an array using Array.prototype.includes. Is this possible? I realize there is a difference between shallow and deep comparison. Is that the reason the below code returns false? I could not find a relevant answer for Array.includes().

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

ronaldodarioc

Add To Favorites

Follow

Total Points: 441

Total Questions: 105

Total Answers: 106

Location: Christmas Island

Member since Sun, Mar 7, 2021

3 Years ago

answered 6 Years ago jeniferjaliyahf · Accepted Answer

Array.includes compares by object identity just like obj === obj2, so sadly this doesn't work unless the two items are references to the same object. You can often use Array.prototype.some() instead which takes a function:

const arr = [{a: 'b'}]

console.log(arr.some(item => item.a === 'b'))

But of course you then need to write a small function that defines what you mean by equality.