Question

121

javascript reverse an array without using reverse()

rated 0 times [ 126] [ 5] / answers: 1 / hits: 36861 / 8 Years ago, tue, november 22, 2016, 12:00:00

I want to reverse an array without using reverse() function like this:

function reverse(array){

    var output = [];

    for (var i = 0; i<= array.length; i++){

        output.push(array.pop());

    }



    return output;

}



console.log(reverse([1,2,3,4,5,6,7]));

However, the it shows [7, 6, 5, 4] Can someone tell me, why my reverse function is wrong? Thanks in advance!

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

leilanichasel

Add To Favorites

Follow

Total Points: 224

Total Questions: 112

Total Answers: 94

Location: Angola

Member since Wed, Apr 13, 2022

2 Years ago

answered 8 Years ago patienceannel · Accepted Answer

array.pop() removes the popped element from the array, reducing its size by one. Once you're at i === 4, your break condition no longer evaluates to true and the loop ends.

One possible solution:

function reverse(array) {

  var output = [];

  while (array.length) {

    output.push(array.pop());

  }



  return output;

}



console.log(reverse([1, 2, 3, 4, 5, 6, 7]));