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/ 8 Years ago, mon, september 26, 2016, 12:00:00
I'm building a simple website which uses mysql as backend. I have a form which has 2 buttons of which one searches data from db and populates the page using Ajax another button updates the new values to db. Now my problem is i can't use both buttons as 'Submit' button.
Ajax Method & Html Form:
<script type=text/javascript>
$(document).ready(function(){
$(document).on('submit', '#update-form', function(){
var data = $(this).serialize();
$.ajax({
type : 'POST',
url : 'search.php',
data : data,
success : function(data){
$(.display).html(data);
}
});
return false;
});
});
</script>
<body>
<div id=update class=tab-pane fade>
<form id=update-form role=form class=container method=post action=search.php>
<h3>Update details</h3>
<table class=display>
<tr class=space>
<td><label>File Number:</label></td>
<td><input type=text class=form-control name=filenum required></td>
</tr>
</table>
<button type=submit class=btn btn-default text-center name=search_btn >Search</button>
<button type=submit class=btn btn-default text-center name=submit_btn formaction=update.php>Update</button>
</form>
</div>
</body>
Now i want to know how can i modify above code so that i can use both button as submit.
Tried withformaction
but it doesn't work because of Ajax method usage.
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