Question

59

Can I break a try - catch in JS without throwing exception?

rated 0 times [ 65] [ 6] / answers: 1 / hits: 24282 / 9 Years ago, thu, august 13, 2015, 12:00:00

I'd like to silently break a try - catch in the try block if a condition applies. ( Without throwing an unneccessary exception )

foo = function(){



    var bar = Math.random() > .5;



    try{



          if( bar ) // Break this try, even though there is no exception here.



          //  This code should not execute if !!bar 



          alert( bar );



    }

    catch( e ){}



    // Code that executes if !!bar



    alert( true );



}



foo();

However, return is not an option, since the function is supposed to continue executing afterwards.

UPDATE

I'd like to still keep up the opportunity to use the finally block.

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

leilanichasel

Add To Favorites

Follow

Total Points: 224

Total Questions: 112

Total Answers: 94

Location: Angola

Member since Wed, Apr 13, 2022

2 Years ago

answered 9 Years ago alfredoc · Accepted Answer

You can label a block and break from it using the break label syntax

as per your edit, finally is still executed

foo = function(){

    var bar = Math.random() > .5;

    omgalabel: try {

        if( bar ) break omgalabel;

        console.log( bar );

        // code 

    }

    catch( e ){

        //  This code should not execute if !!bar 

    }

    finally {

        // Code that executes no matter what

        console.log( true );

    }

}