Question

130

How to 'double' numbers in an array, and save it in a new array

rated 0 times [ 131] [ 1] / answers: 1 / hits: 16037 / 9 Years ago, mon, july 27, 2015, 12:00:00

This is a 2 step problem:

1.) I am trying to 'double' the contents of one array (original Array), save it in a new array (Doubled Array).

2.) Then assign those two arrays to an Object with 2 attributes.
New Object
Orginal Numbers
Doubled Numbers

This is what I have so far, what am I doing wrong?

var numbers = [8, 12, 5, 2, 5, 7];

var doubledNumbers = [];





function doubled(arr){

 for (var i = 0; i < arr.length; i ++){

  var dub = arr[i];

   var dubb = dub*2;

   doubledNumbers.push(dubb);

 }



}



var collectionNumbers = {

  orginialNumbers: numbers,

  doubledNumbers: doubled(numbers)

};



console.log(collectionNumbers);

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

aden

Add To Favorites

Follow

Total Points: 369

Total Questions: 100

Total Answers: 83

Location: Australia

Member since Tue, Oct 19, 2021

3 Years ago

answered 9 Years ago jaredsages · Accepted Answer

What's wrong with your current code, is that your doubled function is returning nothing (which means it's returning undefined).

A better function would look like this:

function doubled (arr) {

    var doubled = [];

    for (var i = 0; i < arr.length; i++) {

        doubled.push(arr[i] * 2);

    }

    return doubled;

}

However, an even better solution would be to just do this:

var collectionNumbers = {

    orginialNumbers: numbers,

    doubledNumbers: numbers.map(function (n) { return n * 2; })

};

.map is awesome.