Question

131

comparing ECMA6 sets for equality

rated 0 times [ 135] [ 4] / answers: 1 / hits: 97019 / 9 Years ago, tue, june 30, 2015, 12:00:00

How do you compare two javascript sets? I tried using == and === but both return false.

a = new Set([1,2,3]);

b = new Set([1,3,2]);

a == b; //=> false

a === b; //=> false

These two sets are equivalent, because by definition, sets do not have order (at least not usually). I've looked at the documentation for Set on MDN and found nothing useful. Anyone know how to do this?

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rhiannab

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3 Years ago

answered 9 Years ago sonja · Accepted Answer

Try this:

const eqSet = (xs, ys) =>

    xs.size === ys.size &&

    [...xs].every((x) => ys.has(x));



const ws = new Set([1, 2, 3]);

const xs = new Set([1, 3, 2]);

const ys = new Set([1, 2, 4]);

const zs = new Set([1, 2, 3, 4]);



console.log(eqSet(ws, xs)); // true

console.log(eqSet(ws, ys)); // false

console.log(eqSet(ws, zs)); // false