Question

13

run next function after setTimeout done

rated 0 times [ 17] [ 4] / answers: 1 / hits: 64976 / 9 Years ago, thu, may 21, 2015, 12:00:00

How to make it work? pls help.

function first() {

    setTimeout((function() {

        $('#q').append('first <br>');

    }), 1000);

}

function second() {

    $('#q').append('second <br>');

}

function third() {

    $('#q').append('third <br>');

}

$.when(first()).done(second()).done(third());

first() runs as last function, i need as first

Fiddle here: JSFIDDLE

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heidys

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4 Years ago

answered 9 Years ago jeffery · Accepted Answer

I am not sure why are you doing this, but if you want to execute them synchronously, you can place the 2nd and 3rd function call inside setTimeout :

function first() {

    setTimeout(function() {

        $('#q').append('first <br>');

        second();

        third();

    }, 1000);

}

function second() {

    $('#q').append('second <br>');

}

function third() {

    $('#q').append('third <br>');

}

first();