Question

25

loop through array, returns odd and even numbers

rated 0 times [ 28] [ 3] / answers: 1 / hits: 42800 / 10 Years ago, wed, november 12, 2014, 12:00:00

I am teaching myself code and am trying to solve this problem:

Write a loop that loops through nums, if the item is even, it adds it to the evens array, if the item is odd, it adds it to the odds array.

This is what I have so far:

var nums = [1,2,34,54,55,34,32,11,19,17,54,66,13];

var evens = [];

var odds = [];



var evenNumbers = function(nums) {

    for (var i = 0; i < nums.length; i++) {



        if ((nums[i] % 2) != 1) {

            evens.push(nums[i]);

                console.log(evens);

        }

        else {

            odds.push(nums[i]);

                console.log(odds);

        }

    }



};



alert(evens);

alert(odds);

They don't return anything and I'm not sure where I'm going wrong, any help would be much appreciated.

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angelicajayleneh

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3 Years ago

answered 10 Years ago pranavrorys · Accepted Answer

You're not actually executing the function. You need to call evenNumbers();

var nums = [1,2,34,54,55,34,32,11,19,17,54,66,13];

var evens = [];

var odds = [];



var evenNumbers = function(nums) {

    for (var i = 0; i < nums.length; i++) {



        if ((nums[i] % 2) != 1) {

            evens.push(nums[i]);

                console.log(evens);

        }

        else {

            odds.push(nums[i]);

                console.log(odds);

        }

    }



};



evenNumbers(nums);

alert(evens);

alert(odds);