I have the following

function doAjax()

{

  var result = false;

  $.ajax(url, data)

    .done(function(){

       // Do a bunch

       // of computation

       // blah blah blah

       result = true;

    }).fail(function(){

       result = false;

    });

  return result;

}



function doSomething()

{

  if ( doAjax() == true )

    console.log('success');

  else

    console.log('failed');

}



function doSomethingElse()

{

  if ( doAjax() == true )

    console.log('success');

  else

    console.log('failed');

}

I have a function that runs some ajax, then returns true or false, depending on whether the ajax was successful or not. This ajax function I call from multiple places in my code.

Because the function ends before the ajax finishes, it always returns false. How do I avoid this?

I have read something suggesting that I do a return $.ajax() in my function and then move the .done() and .fail() functions to my doSomething() and doSomethingElse() functions. However, in my .done() method, I do a BUNCH of computation. Lots of code. So the problem is, that if I move the .done() function to my other functions, I am duplicating a bunch of code.

How do I avoid this? Just wrap the computation into it's own function and call it wherever necessary?