Question

124

traverse a string char by char javascript

rated 0 times [ 130] [ 6] / answers: 1 / hits: 15304 / 10 Years ago, mon, august 25, 2014, 12:00:00

function SimpleSymbols(str) { 

    var letter =['a','b','c','d','e','f','g','h','i','j',

    'k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];



    var newstr = ;

    for (var i = 0; i<str.length; i++){

        if (str.charAt(i).toLowerCase() in letter){

            newstr += M;

        }

        else{

            newstr += X;

        }

    }



return newstr; 



}

If str is Argument goes here it returns XXXXXXXXX. WHy doesn't it return MMMMMMMMMM?

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dawnc

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3 Years ago

answered 10 Years ago kaceyr · Accepted Answer

you do not look up an entry in an array with in. use indexOf() to find the position of an array entry. indexOf() will return the position or -1 if no entry is found.

for (var i = 0; i<str.length; i++){

    var strChar = str.charAt(i).toLowerCase();



    if ( letter.indexOf(strChar) >= 0 ) {

        newstr += M;

    }

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