Question

126

TypeError: not a constructor

rated 0 times [ 128] [ 2] / answers: 1 / hits: 24451 / 10 Years ago, tue, june 24, 2014, 12:00:00

I am trying to use OOP based javascript/jQuery. I want to put all my JS function inside a class, so it can be easily overridden/hooked.

I tried with a simple OOP code, but its giving type error: not a constructor.
Please have a look at my code and guide me what is wrong in my code, and how to fix it.

var myTestClass = {

    testAttribute : 'test', // atttribute

    testMethod : function(){ alert( testAttribute); }

};



var my = new myTestClass();

my.testMethod();

Thanks

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rafael

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3 Years ago

answered 10 Years ago amari · Accepted Answer

to view your alert:

var myTestClass = {

    testAttribute: 'test', 

    testMethod: function () { alert(this.testAttribute); }





  };





  myTestClass.testMethod();

another approach:

function myTClass(){

    var testAttribute = 'test';

    this.testMethod = function () {

      alert(testAttribute);

    };



  }



  var obj = new myTClass();

  obj.testMethod();

Lazy Inheritance example:

function myTClass(){



    this.testMethod = function () {

      alert(this.testAttribute);

    };



  }



  myTClass.prototype.testAttribute = 'test';



  var obj = new myTClass();

  obj.testMethod();



  function derivedTClass() {

    myTClass.call(this);

    this.testMethod = function () {

      alert('derived ' + this.testAttribute);

    };

  }



  derivedTClass.prototype = Object.create(myTClass.prototype);



  var obj2 = new derivedTClass();

  obj2.testMethod();



  derivedTClass.prototype.constructor = derivedTClass;