I have a few strings like so:
str1 = 00001011100000; // 10111
str2 = 00011101000000; // 11101
...
I would like to strip the leading AND closing zeros from every string using regex with ONE operation.
So far I used two different functions but I would like to combine them together:
str.replace(/^0+/,'').replace(/0+$/,'');
You can just combine both of your regex using an OR clause (|):
var r = '00001011100000'.replace(/^0+|0+$/g, );
//=> 10111
update: Above regex solutions replaces 0 with an empty string. To prevent this problem use this regex:
var repl = str.replace(/^0+(d)|(d)0+$/gm, '$1$2');
RegEx Breakup:
^: Assert start0+: Match one or more zeroes(d): Followed by a digit that is captured in capture group #1|: OR(d): Match a digit that is captured in capture group #20+: Followed by one or more zeroes $: Assert endReplacement:
Here we are using two back-references of the tow capturing groups:
$1$2
That basically puts digit after leading zeroes and digit before trailing zeroes back in the replacement.
