So I tried this:
if (/^[a-zA-Z]/.test(word)) {
// code
}
It doesn't accept this :
But it does accept this: word word, which does contain a space :/
Is there a good way to do this?
With /^[a-zA-Z]/ you only check the first character:
^: Assert position at the beginning of the string[a-zA-Z]: Match a single character present in the list below:a-z: A character in the range between a and zA-Z: A character in the range between A and ZIf you want to check if all characters are letters, use this instead:
/^[a-zA-Z]+$/.test(str);
^: Assert position at the beginning of the string[a-zA-Z]: Match a single character present in the list below:+: Between one and unlimited times, as many as possible, giving back as needed (greedy)a-z: A character in the range between a and zA-Z: A character in the range between A and Z$: Assert position at the end of the string (or before the line break at the end of the string, if any)Or, using the case-insensitive flag i, you could simplify it to
/^[a-z]+$/i.test(str);
Or, since you only want to test, and not match, you could check for the opposite, and negate it:
!/[^a-z]/i.test(str);
