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rated 0 times [  61] [ 5]  / answers: 1 / hits: 49074  / 11 Years ago, tue, november 19, 2013, 12:00:00

I'm trying to create popup that can show when mouse over it and will stay when click on the link .The problem is I already make the popup will show up when the mouse over it but it will disappear when the mouse leave .How can I make the popup will stay show up when clicked .This is my code :



HTML



<div id=pop1 class=popbox>
<h2>Job Info Search</h2>
<h2>WRKNo : <input type=text /></h2>
<h2>Result</h2>
<p>Customer Name : <input type=text /></p>
<p>Caller Number : <input type=text /></p>
<p>Complosed : <input type=text /></p>
<p>Cate : <input type=text /></p>
<p>Det : <input type=text /></p>
<p>Feedback : <input type=text /></p>
<p>WRKNo : <input type=text /></p>
</div>




This is a popbox test. <a href=# class=popper data-popbox=pop1>Hover here</a> to see how it works.


CSS



.popbox {
display: none;
position: absolute;
z-index: 99999;
width: 400px;
padding: 10px;
background: #EEEFEB;
color: #000000;
border: 1px solid #4D4F53;
margin: 0px;
-webkit-box-shadow: 0px 0px 5px 0px rgba(164, 164, 164, 1);
box-shadow: 0px 0px 5px 0px rgba(164, 164, 164, 1);
}
.popbox h2
{
background-color: #4D4F53;
color: #E3E5DD;
font-size: 14px;
display: block;
width: 100%;
margin: -10px 0px 8px -10px;
padding: 5px 10px;
}


Javascript



<script src=http://ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js type=text/javascript></script>
<script>
$(function() {
var moveLeft = 0;
var moveDown = 0;
$('a.popper').hover(function(e) {

var target = '#' + ($(this).attr('data-popbox'));

$(target).show();
moveLeft = $(this).outerWidth();
moveDown = ($(target).outerHeight() / 2);
}, function() {
var target = '#' + ($(this).attr('data-popbox'));
$(target).hide();
});

$('a.popper').mousemove(function(e) {
var target = '#' + ($(this).attr('data-popbox'));

leftD = e.pageX + parseInt(moveLeft);
maxRight = leftD + $(target).outerWidth();
windowLeft = $(window).width() - 40;
windowRight = 0;
maxLeft = e.pageX - (parseInt(moveLeft) + $(target).outerWidth() + 20);

if(maxRight > windowLeft && maxLeft > windowRight)
{
leftD = maxLeft;
}

topD = e.pageY - parseInt(moveDown);
maxBottom = parseInt(e.pageY + parseInt(moveDown) + 20);
windowBottom = parseInt(parseInt($(document).scrollTop()) + parseInt($(window).height()));
maxTop = topD;
windowTop = parseInt($(document).scrollTop());
if(maxBottom > windowBottom)
{
topD = windowBottom - $(target).outerHeight() - 20;
} else if(maxTop < windowTop){
topD = windowTop + 20;
}

$(target).css('top', topD).css('left', leftD);


});

});
</script>


Any ideas how I can do this?


More From » jquery

 Answers
21

Try this:



$('a.popper').hover(function (e) {    
var target = '#' + ($(this).attr('data-popbox'));
$(target).show();
moveLeft = $(this).outerWidth();
moveDown = ($(target).outerHeight() / 2);
}, function () {
var target = '#' + ($(this).attr('data-popbox'));
if (!($(a.popper).hasClass(show))) {
$(target).hide(); //dont hide popup if it is clicked
}
});
$('a.popper').click(function (e) {
var target = '#' + ($(this).attr('data-popbox'));
if (!($(this).hasClass(show))) {
$(target).show();
}
$(this).toggleClass(show);
});


FIDDLE here.


[#74201] Monday, November 18, 2013, 11 Years  [reply] [flag answer]
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