Question

46

How do I insert PHP variable inside jQuery/JavaScript properly?

rated 0 times [ 47] [ 1] / answers: 1 / hits: 20875 / 11 Years ago, mon, november 11, 2013, 12:00:00

This code works when running the application, but Dreamweaver is giving a syntax error. It doesn't like the question mark there. I like DW to be syntax error free. Is there a different way to write this? I have DW cs5.5 I can't upgrade Dreamweaver version.

    if ( $('#postage6').val() == Your Permit Standard ) {

        $('#postage6rate').val('<?php echo $your_permit_standard; ?>');

    }

Putting a backslash before the question mark just makes it print like this, which is not right.

    if ( $('#postage6').val() == Your Permit Standard ) {

        $('#postage6rate').val('<?php echo $your_permit_standard; ?>');

    }

when it renders, there is supposed to be a value like this:

    if ( $('#postage6').val() == Your Permit Standard ) {

        $('#postage6rate').val('0.333');

    }

Also this doesn't work:

    if ( $('#postage6').val() == Your Permit Standard ) {

        var somevar = <?php echo $your_permit_standard; ?>;

        $('#postage6rate').val(somevar);

    }

The syntax error just transfers from the line where the PHP variable was to the new line where the PHP variable is.

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

briannar

Add To Favorites

Follow

Total Points: 354

Total Questions: 103

Total Answers: 101

Location: Japan

Member since Sat, Jun 6, 2020

4 Years ago

answered 11 Years ago jazminkyrap · Accepted Answer

You could define the value in a separate php block:

<script type=text/javascript>

   var value = '<?=$your_permit_standard?>';

</script>

And then use it in your JS:

if ( $('#postage6').val() == Your Permit Standard ) {

    $('#postage6rate').val(value);

}

But then you would be introducing JS dependency in PHP, which I wouldn't recommend, but since you're mixing both anyway...