Question

104

Removing %20 from URL parameters

rated 0 times [ 110] [ 6] / answers: 1 / hits: 21974 / 12 Years ago, wed, february 27, 2013, 12:00:00

I know you need to use some variant of decodeURIComponent() to do something like this, but since I'm still fairly new to coding and using some code I found on the net for my purposes, I'm not sure how to go about changing it to suit my needs.

What I have is a function that gets each URL parameter I need out of the URL (of which there are many). I have to use these variables for other functions as parameters and also to display on the page, and I can't get the %20's to disappear.

function getUrlVars() {

            var vars = {};

            parts = window.location.href.replace(/[?&]+([^=&]+)=([^&]*)/gi, function(m,key,value) {

            vars[key] = value;

            });

            return vars;

        }

Where I get each variable using:

var markname = getUrlVars()[mname];

I've tried to put decodeURIComponent() in different places in that function, but I can't seem to get it to work. I'm also not sure if it needs to use value or vars.

value = decodeURIComponent(value);

Or something like that...

Any help would be appreciated! Thanks!

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braidenv

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2 Years ago

answered 12 Years ago destiniemartinac · Accepted Answer

decodeURIComponent as you posted should work fine. You might as well replace plus signs with spaces, and don't forget to decode the key as well:

function getUrlVars() {

    var url = window.location.href,

        vars = {};

    url.replace(/[?&]+([^=&]+)=([^&]*)/gi, function(m, key, value) {

         key = decodeURIComponent(key);

         value = decodeURIComponent(value);

         vars[key] = value;

    });

    return vars;

}