Question

132

JavaScript object pushed into an array

rated 0 times [ 134] [ 2] / answers: 1 / hits: 21983 / 12 Years ago, wed, january 23, 2013, 12:00:00

Possible Duplicate:

How do I correctly clone a JavaScript object?

I have this code:

var temp = [];

var obj = {name:1};

temp.push(obj);

obj.name = 2;

temp.push(obj);

What I'm expecting to be true:

temp[0].name == 1 && temp[1].name == 2;

What actually happens:

temp[0].name == 2 && temp[1].name == 2;

Why does this happen, and how I can get what I'm expecting?

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tiasavannahw

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3 Years ago

answered 12 Years ago angelr · Accepted Answer

JavaScript arrays hold references to objects, rather than objects themselves. When you push an object into the array it does not create a new object, but it simply puts a reference to the object, that obj also points to, into the array.

So in the end obj, temp[0], and temp1 all point to the same object. To actually create a completely new object, you can use Object.create() or jQuery.extend({},obj). Though in your case it's easy enough just to create a new simple object using var newobj = {name=2}