Thursday, May 23, 2024
 Popular · Latest · Hot · Upcoming
73
rated 0 times [  75] [ 2]  / answers: 1 / hits: 18061  / 12 Years ago, tue, november 27, 2012, 12:00:00

Basically, I have a very simple website where the root directory looks like:



/images/
index.html
stuff.js


I want some way to recursively iterate through every file in the /images/ directory and display them in order in a section of my website. So for example, if /images/ contained:



images/a/a.png
images/b.png
images/c.jpg
....


then somewhere in index.html would contain:



<img src=images/a/a.png />
<img src=images/b.png />
<img src=images/c.jpg />
....


My first idea was to do this using the document.write() function in stuff.js, but I couldn't find a good way to iterate through the local file directory in Javascript. I saw something about AJAX, but all of those examples involved editing an existing file, which I obviously don't want to do.



My current solution is just to manual create an array of strings containing all of the files in /images/, but doing this makes me think There's got to be a better way!



Let me know if I've been unclear.



Thanks!


More From » html

 Answers
81

Perhaps the best way to do this is to use a server-sided language to do it for you, and to use an asynchronous Javascript request to display the data.



This sample uses PHP to list all the files in a specified directory, and an xmlhttprequest to load this output and convert the results into image tags:






getimages.php:



<?php

//The directory (relative to this file) that holds the images
$dir = Images;


//This array will hold all the image addresses
$result = array();

//Get all the files in the specified directory
$files = scandir($dir);


foreach($files as $file) {

switch(ltrim(strstr($file, '.'), '.')) {

//If the file is an image, add it to the array
case jpg: case jpeg:case png:case gif:

$result[] = $dir . / . $file;

}
}

//Convert the array into JSON
$resultJson = json_encode($result);

//Output the JSON object
//This is what the AJAX request will see
echo($resultJson);

?>





index.html (same directory as getimages.php):



<!DOCTYPE html>
<html>
<head>
<title>Image List Thing</title>
</head>
<body>

<div id=images></div>
<input type=button onclick=callForImages() value=Load />

<script>

//The div element that will contain the images
var imageContainer = document.getElementById(images);



//Makes an asynch request, loading the getimages.php file
function callForImages() {

//Create the request object
var httpReq = (window.XMLHttpRequest)?new XMLHttpRequest():new ActiveXObject(Microsoft.XMLHTTP);

//When it loads,
httpReq.onload = function() {

//Convert the result back into JSON
var result = JSON.parse(httpReq.responseText);

//Show the images
loadImages(result);
}

//Request the page
try {
httpReq.open(GET, getimages.php, true);
httpReq.send(null);
} catch(e) {
console.log(e);
}

}


//Generates the images and sticks them in the container
function loadImages(images) {

//For each image,
for(var i = 0; i < images.length; i++) {

//Make a new image element, setting the source to the source in the array
var newImage = document.createElement(img);
newImage.setAttribute(src, images[i]);

//Add it to the container
imageContainer.appendChild(newImage);

}

}

</script>

</body>
</html>


Note that this is only an example. You'll probably want to make sure that the AJAX call is successful, and that the JSON conversion works both in the server code and on the client.


[#81766] Monday, November 26, 2012, 12 Years  [reply] [flag answer]
Only authorized users can answer the question. Please sign in first, or register a free account.
kiyam

Total Points: 448
Total Questions: 96
Total Answers: 92

Location: Philippines
Member since Sat, Jul 11, 2020
4 Years ago
;