Question

158

Why doesn't console.log work when passed as a parameter to forEach?

rated 0 times [ 162] [ 4] / answers: 1 / hits: 15679 / 12 Years ago, fri, march 9, 2012, 12:00:00

This is just out of curiosity, but do any of you have an idea why this code won't work?

[1, 2, 3, 4, 5].forEach(console.log);



// Prints 'Uncaught TypeError: Illegal invocation' in Chrome

On the other hand, this seems to work fine:

[1, 2, 3, 4, 5].forEach(function(n) { console.log(n) });

So... ?

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paolam

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3 Years ago

answered 12 Years ago byrondonavanc · Accepted Answer

Actually as @SLaks pointed out, console.log seems to be using this internally and when it's passed as a parameter this now refers to the array instance.

The workaround for that is simply:

var c = console.log.bind(console);
[1,2,3,4,5].forEach(c);