Question

13

rated 0 times [ 15] [ 2] / answers: 1 / hits: 23267 / 13 Years ago, fri, february 10, 2012, 12:00:00

I'm trying to use this and it doesn't appear to be working. I'm guessing it's just not an option, but want to confirm. Is this valid?

(if_it_is) ? thats_cool();

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Member since Sat, Jul 25, 2020

4 Years ago

answered 13 Years ago analiseb · Accepted Answer

You can use && there:

if_it_is && thats_cool();

It is basically equal to:

if (your_expression){

   thats_cool();

}