Question

141

split an array into two arrays based on odd/even position

rated 0 times [ 145] [ 4] / answers: 1 / hits: 28258 / 13 Years ago, mon, november 14, 2011, 12:00:00

I have an array Arr1 = [1,1,2,2,3,8,4,6].

How can I split it into two arrays based on the odd/even-ness of element positions?

subArr1 = [1,2,3,4]

subArr2 = [1,2,8,6]

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danyelletyanah

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3 Years ago

answered 13 Years ago isham · Accepted Answer

You could try:

var Arr1 = [1,1,2,2,3,8,4,6],

    Arr2 = [],

    Arr3 = [];



for (var i=0;i<Arr1.length;i++){

    if ((i+2)%2==0) {

        Arr3.push(Arr1[i]);

    }

    else {

        Arr2.push(Arr1[i]);

    }

}



console.log(Arr2);

JS Fiddle demo.