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rated 0 times [  92] [ 2]  / answers: 1 / hits: 27630  / 13 Years ago, wed, august 3, 2011, 12:00:00

I have a very long page that dynamically loads images as users scroll through.



However, if a user quickly scrolls away from a certain part of the page, I don't want the images to continue loading in that now out-of-view part of the page.



There are lots of other requests happening on the page simultaneously apart from image loading, so a blunt window.stop() firing on the scroll event is not acceptable.



I have tried removing & clearing the img src attributes for images that are no longer in view, however, since the request was already started, the image continues to load.



Remember that the image src was filled in as the user briefly scrolled past that part of the page. Once past though, I couldn't get that image from stop loading without using window.stop(). Clearing src didn't work. (Chrome & FF)



Similar posts I found that get close, but don't seem to solve this problem:




More From » jquery

 Answers
27

What you are trying to do is the wrong approach, as mentioned by nrabinowitz. You can't just cancel the loading process of an image (setting the src attribute to an empty string is not a good idea). In fact, even if you could, doing so would only make things worst, as your server would continually send data that would get cancelled, increasing it's load factor and slow it down. Also, consider this:




  1. if your user scroll frenetically up and down the page, he/she will expect some loading delays.

  2. having a timeout delay (ex: 200 ms) before starting to load a portion of the page is pretty acceptable, and how many times will one stop and jump after 200 ms interval on your page? Even it it happens, it comes back to point 1

  3. how big are your images? Even a slow server can serve about a few tens of 3Kb thunbnails per second. If your site has bigger images, consider using low and hi resolution images with some components like lightBox



Often, computer problems are simply design problems.



** EDIT **



Here's an idea :




  1. your page should display DIV containers with the width and height of the expected image size (use CSS to style). Inside of each DIV, add an link. For example :



    <div class=img-wrapper thumbnail>
    <a href=http://www.domain.com/path/to/image>Loading...</a>
    </div>

  2. Add this Javascript (untested, the idea is self describing)



    $(function() {

    var imgStack;
    var loadTimeout;

    $(window).scroll(function() {
    imgStack = null;
    if (loadTimeout) clearTimeout(loadTimeout);

    loadTimeout = setTimeout(function() {

    // get all links visible in the view port
    // should be an array or jQuery object
    imgStack = ...

    loadNextImage();
    }, 200); // 200 ms delay
    });

    function loadNextImage() {
    if (imgStack && imgStack.length) {
    var nextLink = $(imgStack.pop()); // get next image element

    $('<img />').attr('src', nextLink.attr('href'))
    .appendTo(nextLink.parent())
    .load(function() {
    loadNextImage();
    });

    // remove link from container (so we don't precess it twice)
    nextLink.remove();
    }
    };

    });


[#90840] Tuesday, August 2, 2011, 13 Years  [reply] [flag answer]
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