Question

80

rated 0 times [ 82] [ 2] / answers: 1 / hits: 36433 / 14 Years ago, mon, january 10, 2011, 12:00:00

Normally I'm doing it this way:

for(i=0;i<elem.parentNode.length;i++) {

  if (elem.parentNode[i] == elem) //.... etc.. etc...

}

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Location: Guernsey

Member since Tue, Jul 6, 2021

3 Years ago

answered 14 Years ago lucianod · Accepted Answer

You could count siblings...
The childNodes list includes text and element nodes-

function whichChild(elem){

    var  i= 0;

    while((elem=elem.previousSibling)!=null) ++i;

    return i;

}