This is an example of the string that's being worked with:

xxxxxx[xxxxxx][7][xxxxxx][9][xxxxxx]

I'm having a little trouble matching the second occurrence of a match, I want to return the 2nd square brackets with a number inside. I have some regex finding the first square backets with numbers in a string:

[+[0-9]+]

This returns [7], however I want to return [9].

I'm using Javascript's replace function, the following regex matches the second occurrence (the [9]) in regex testeing apps, however it isn't replaced correctly in the Javascript replace function:

(?:.*?([+[0-9]+])){2}

My question is how do I use the above regex to replace the [9] in Javasctipt or is there another regex that matches the second occurrence of a number in square brackets.

Cheers!