Question

129

URL regex validation

rated 0 times [ 134] [ 5] / answers: 1 / hits: 51092 / 14 Years ago, tue, november 30, 2010, 12:00:00

i made that:

 /^(http[s]?://){0,1}(www.){0,1}[a-zA-Z0-9.-]+.[a-zA-Z]{2,5}[.]{0,1}

and checked it with a validator but on my page it is not working:

var re = /^(http[s]?://){0,1}(www.){0,1}[a-zA-Z0-9.-]+.[a-zA-Z]{2,5}[.]{0,1};

if (!re.test(url)) { 

    alert(url error);

    return false;

}

i get this error

Webpage error details



User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; WOW64; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; .NET4.0C; .NET4.0E)

Timestamp: Tue, 30 Nov 2010 14:23:10 UTC





Message: Expected ')' in regular expression

Line: 781

Char: 23

Code: 0

URI: http://*************************

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

aleenamarinr

Add To Favorites

Follow

Total Points: 610

Total Questions: 109

Total Answers: 118

Location: Mayotte

Member since Mon, Sep 12, 2022

2 Years ago

answered 14 Years ago madilynndiannac · Accepted Answer

You have to escape your special characters (/ and that . after www in this case) and att the missing trailing /, like this:

var re = /^(http[s]?://){0,1}(www.){0,1}[a-zA-Z0-9.-]+.[a-zA-Z]{2,5}[.]{0,1}/;

if (!re.test(url)) { 

    alert(url error);

    return false;

}