Monday, May 20, 2024
 Popular · Latest · Hot · Upcoming
110
rated 0 times [  114] [ 4]  / answers: 1 / hits: 102738  / 15 Years ago, tue, december 22, 2009, 12:00:00
<script>
function urlencode(str) {
return escape(str).replace('+', '%2B').replace('%20', '+').replace('*', '%2A').replace('/', '%2F').replace('@', '%40');
}
$('input#q').keyup(function(e) {
if(e.keyCode == 13) {
if($('input#q').val().length > 2)
{
$('input#q').val() = urlencode($('input#q').val());
document.search_form.submit();
}
}
});
$('input#search').click(function() {
if($('input#q').val().length > 2)
{
$('input#q').val() = urlencode($('input#q').val());
document.search_form.submit();
}
});
</script>


when i click the search button i get the following error : Uncaught ReferenceError: Invalid left-hand side in assignment
But the code is actually the same as when i press enter. Can someone explain?


More From » jquery

 Answers
49

You can't assign a new value to the result of a function



$('input#q').val() = urlencode($('input#q').val());


Use this instead:



$('input#q').val(urlencode($('input#q').val()))


It wouldn't work with the keypress either - maybe the page is simply submitted after the same js error occurs.


[#98016] Friday, December 18, 2009, 15 Years  [reply] [flag answer]
Only authorized users can answer the question. Please sign in first, or register a free account.
tye

Total Points: 415
Total Questions: 103
Total Answers: 116

Location: Iraq
Member since Fri, Jun 5, 2020
4 Years ago
;