Question

85

ASP.Net double-click problem

rated 0 times [ 90] [ 5] / answers: 1 / hits: 25027 / 15 Years ago, wed, september 30, 2009, 12:00:00

having a slight problem with an ASP.net page of mine. If a user were to double click on a submit button it will write to the database twice (i.e. carry out the 'onclick' method on the imagebutton twice)

How can I make it so that if a user clicks on the imagebutton, just the imagebutton is disabled?

I've tried:

<asp:ImageButton 

     runat=server 

     ID=VerifyStepContinue 

     ImageUrl=image src 

     ToolTip=Go 

     TabIndex=98 

     CausesValidation=true 

     OnClick=methodName 

     OnClientClick=this.disabled = true; />

But this OnClientClick property completely stops the page from being submitted! Any help?

Sorry, yes, I do have Validation controls... hence the icky problem.

Working on this still, up to this point now:

ASP code:

 <asp:TextBox ID=hidToken runat=server Visible=False Enabled=False></asp:TextBox>

 ...

 <asp:ImageButton runat=server ID=InputStepContinue Name=InputStepContinue ImageUrl=imagesrc ToolTip=Go TabIndex=98 CausesValidation=true OnClick=SubmitMethod OnClientClick=document.getElementById('InputStepContinue').style.visibility='hidden'; />

C# code:

         private Random

    random = new Random();





    protected void Page_Load(object sender, EventArgs e)

    {

        //Use a Token to make sure it has only been clicked once.

        if (Page.IsPostBack)

        {

            if (double.Parse(hidToken.Text) == ((double)Session[NextToken]))

            {

                InputMethod();

            }

            else

            {

                // double click

            }

        }



        double next = random.Next();



        hidToken.Text = next + ;

        Session[NextToken] = next;

Actually... this nearly works. The double click problem is pretty much fixed (yay!) The image still isn't hidden though.

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elaine

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3 Years ago

answered 15 Years ago hallie · Accepted Answer

The general approach is twofold.

Serverside:

On load of the page, generate a token (using System.Random), save it in the session, and write it to a hidden form field

On submit, check that the hidden form field equals the session variable (before setting it again)

Do work

Clientside:

Similar to what you have, but probably just hide the button, and replace it with some text like 'submitting'.

The important thing to note, client side, is that the user may cancel the post by hitting 'escape', so you should consider what to do here (depending on how far along they are the token won't be used, so you'll need to bring the button back from being disabled/hidden).

Complete example follows:

C# (includes code to see it in action):

<html>

<head runat=server>

    <title>double-click test</title>

    <script language=c# runat=server>

    private Random

        random = new Random();



    private static int

        TEST = 0;



    public void Page_Load (object sender, EventArgs ea)

    {

        SetToken();

    }



    private void btnTest_Click (object sender, EventArgs ea)

    {

        if( IsTokenValid() ){

            DoWork();

        } else {

            // double click

            ltlResult.Text = double click!;

        }

    }



    private bool IsTokenValid ()

    {

        bool result = double.Parse(hidToken.Value) == ((double) Session[NextToken]);

        SetToken();

        return result;

    }



    private void SetToken ()

    {

        double next = random.Next();



        hidToken.Value       = next + ;

        Session[NextToken] = next;

    }





    private void DoWork ()

    {

        TEST++;

        ltlResult.Text = DoWork():  + TEST + .;

    }

    </script>

</head>

<body>

    <script language=javascript>

        var last = null;

        function f (obj)

        {

            obj.src = http://www.gravatar.com/avatar/4659883ec420f39723c3df6ed99971b9?s=32&d=identicon&r=PG;

            // Note: Disabling it here produced strange results. More investigation required.

            last = obj;

            setTimeout(reset(), 1 * 1000);

            return true;

        }



        function reset ()

        {

            last.src = http://www.gravatar.com/avatar/495ce8981a5127a9fd24bd72e7e3664a?s=32&d=identicon&r=PG;

            last.disabled = false;

        }

    </script>

    <form id=form1 runat=server>

        <asp:HiddenField runat=server ID=hidToken />

        <asp:ImageButton runat=server ID=btnTest

            OnClientClick=return f(this);

            ImageUrl=http://www.gravatar.com/avatar/495ce8981a5127a9fd24bd72e7e3664a?s=32&d=identicon&r=PG OnClick=btnTest_Click />

        <pre>Result: <asp:Literal runat=server ID=ltlResult /></pre>

    </form>

</body>

</html>