Question

165

How to get JavaScript caller function line number and caller source URL

rated 0 times [ 168] [ 3] / answers: 1 / hits: 137072 / 15 Years ago, thu, august 27, 2009, 12:00:00

I am using the following for getting the JavaScript caller function name:

var callerFunc = arguments.callee.caller.toString();

callerFuncName = (callerFunc.substring(callerFunc.indexOf(function) + 8, callerFunc.indexOf(()) || anoynmous)

Is there a way to discover the line number from which the method was called?

Also, is there a way to get the name of the JavaScript file the method was called from? Or the source URL?

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4 Years ago

answered 15 Years ago jenamackennac · Accepted Answer

This works for me in chrome/QtWebView

function getErrorObject(){

    try { throw Error('') } catch(err) { return err; }

}



var err = getErrorObject();

var caller_line = err.stack.split(n)[4];

var index = caller_line.indexOf(at );

var clean = caller_line.slice(index+2, caller_line.length);