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69

Javascript use single await in ternary operator

rated 0 times [ 73] [ 4] / answers: 1 / hits: 7903 / 4 Years ago, sun, may 31, 2020, 12:00:00

I have a situation I want to use await in a ternary operator. I want to set a value to either a literal value or the resolve value of a promise, depending on a condition. Hopefully the code below will help describe what I want to do, but I am pretty sure it is not correct so consider it pseudo code.

const val = checkCondition ? literal value : await promiseGetValue();

Where promiseGetValue() returns a promise which resolves to a literal value. What is the correct way to do this?

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matteo

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answered 4 Years ago jarrettw · Accepted Answer

This is actually a valid syntax, just for clarity u can surround the await promiseGetValue() with brackets. here is a demo of this syntax.

const returnPromise = () => Promise.resolve('world')

const f = async () => {

   const x = true ? 'hello' : await returnPromise()

    const y = false ? 'hello' : await returnPromise()

    console.log(x,y)



}

f()