Question

29

Check if at least two elements in an array are greater than zero - JavaScript/Typescript

rated 0 times [ 34] [ 5] / answers: 1 / hits: 10641 / 4 Years ago, mon, february 17, 2020, 12:00:00

Is there a smart way to find out if there are at least two values greater than 0 in an array and return true? And false in the opposite case?

(hypothetical and wrong example using some):

const a = [9, 1, 0];

const b = [0, 0, 0];

const c = [5, 0, 0];



const cond = (el) => el > 0 && somethingElseMaybe;



console.log(a.some(cond)); // print true

console.log(b.some(cond)); // print false

console.log(c.some(cond)); // print false

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taylert

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answered 4 Years ago leslijessalyng · Accepted Answer

To avoid wasted effort, you should stop the checking as soon as the condition is met. I think this meets your requirement.

function twoGreaterThanZero(arr) { 

    let counter = 0

    for(let x of arr) {

        if(x > 0 && (++counter > 1)) return true

    }

    return false

}



const a = [9, 1, 0]

const b = [0, 0, 0]

const c = [5, 0, 0]



console.log(twoGreaterThanZero(a)) // print true

console.log(twoGreaterThanZero(b)) // print false

console.log(twoGreaterThanZero(c)) // print false