Question

170

rated 0 times [ 174] [ 4] / answers: 1 / hits: 18977 / 7 Years ago, thu, december 28, 2017, 12:00:00

I have an object an a function which accept arguments, I would like to spread the objects so each property is an argument in that function.

What am I doing wrong in my code?

const args = {

    a: 1

    b: 2

}



const fn = (a, b) => a + b



// i am trying with no success

console.log(fn(...args))

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answered 7 Years ago kristinsonjab · Accepted Answer

You can use ES6 object destructuring on passed parameter and then just pass your object.

const args = {a: 1, b: 2}



const fn = ({a, b}) => a + b

console.log(fn(args))

You can also set default values for those properties.

const args = {b: 2}



const fn = ({a = 0, b = 0}) => a + b

console.log(fn(args))