Can I avoid declaring a useless variable when array destructuring when I am only interested in array values beyond index 0?
In the following, I want to avoid declaring a, I am only interested in index 1 and beyond.
// How can I avoid declaring a?
const [a, b, ...rest] = [1, 2, 3, 4, 5];
console.log(a, b, rest);
Can I avoid declaring a useless variable when array destructuring when I am only interested in array values beyond index 0?
Yes, if you leave the first index of your assignment empty, nothing will be assigned. This behavior is explained here.
// The first value in array will not be assigned
const [, b, ...rest] = [1, 2, 3, 4, 5];
console.log(b, rest);You can use as many commas as you like wherever you like, except after a rest element:
const [, , three] = [1, 2, 3, 4, 5];
console.log(three);
const [, two, , four] = [1, 2, 3, 4, 5];
console.log(two, four);The following produces an error:
const [, ...rest,] = [1, 2, 3, 4, 5];
console.log(rest);
