Question

198

Verify is Armstrong number with Javascript

rated 0 times [ 200] [ 2] / answers: 1 / hits: 18660 / 7 Years ago, thu, august 31, 2017, 12:00:00

I need to do a code to verify whether or not the entered number is an Armstrong number, but my code does not work for every number.

Could anyone tell me what am I missing? Are there any other ways to do this?

Thank you!

let e, x, d = 0;

let b = prompt(Enter a number);

x=b;



while (x > 0) {

  e = x % 10;

  x = parseInt(x/10);

  d = d + (e*e*e);

}



if (b==d)

   alert(given number is an armstrong number);

else

   alert(given number is not an armstrong number);

<!DOCTYPE HTML>

<html>

<head>

        <title>Armstrong</title>

</head>

<body>

</body>

</html>

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kinsley

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answered 7 Years ago destiniemartinac · Accepted Answer

You can try for This, May this help for you:

 <!DOCTYPE HTML>

    <html>

        <head>

            <title>Armstrong</title>

        </head>

            <body>



            </body>

            </html>



    <script>

    var z,e,x,d=0;

    var b=prompt(Enter a number);

    x=parseInt(b);

    while(x>0)  //Here is the mistake

    {

    e=x%10;

    x=parseInt(x/10);

    d=d+(e*e*e);

    console.log(d: +d+ e: +e);



    }

    if(parseInt(b)==d){



    alert(given no is amstrong number);

    }

    else {



    alert(given no is not an amstrong number);

    }

    </script>