I wrote the following node.js file:

var csv = require('csv-parser');

var fs = require('fs')

var Promise = require('bluebird');

var filename = devices.csv;

var devices;



Promise.all(read_csv_file(devices.csv), read_csv_file(bugs.csv)).then(function(result) {

    console.log(result);

});





function read_csv_file(filename) {

    return new Promise(function (resolve, reject) {

            var result = []

            fs.createReadStream(filename)

                .pipe(csv())

                .on('data', function (data) {

                    result.push(data)

                }).on('end', function () {

                resolve(result);

            });

    })

}

As you can see, I use Promise.all in order to wait for both operations of reading the csv files. I don't understand why but when I run the code the line 'console.log(result)' is not committed.

My second question is I want that the callback function of Promise.all.then() accepts two different variables, while each one of them is the result of the relevant promise.