I am getting this error message at the console for line:

var dataString = 'search='+ searchid;

at following script:

$(function(){

    $(.search).keyup(function() { 

        var searchid = $(this).val();

        var dataString = 'search='+ searchid;

        if(searchid!='') {

            $.ajax({

                type: POST,

                url: classes/search.php,

                data: dataString,

                cache: false,

                success: function(html) {

                    $(#result).html(html).show();

                }

            });

        }

        return false;    

    });

});

What is wrong there?