You can use the replacer. The second parameter provided by JSON.stringify.Replacer could be a function or array.

In your case we can create a function which replaces all the special characters with a blank space.The below example replaces the whitespaces and underscores.

function replacer(key, value) {

  return value.replace(/[^ws]/gi, '');

}



var foo = {a:1,b:2};

var jsonString = JSON.stringify(foo, replacer);

If you simply want to replace the one special character, use:

JSON.stringify({ a: 1, b: 2 }, null, 't');

For more information on replacer, check the MDN page JSON.stringify().