OBJECTIVE

Given two numbers in an array, sum all the numbers including (and between) both integers (e.g [4,2] -> 2 + 3 + 4 = 9).

I've managed to solve the question but was wondering if there is a more elegant solution (especially using Math.max and Math.min) - see below for more questions...

MY SOLUTION

//arrange array for lowest to highest number

function order(min,max) {

  return min - max;

}





function sumAll(arr) {

  var list = arr.sort(order);

  var a = list[0]; //smallest number

  var b = list[1]; //largest number

  var c = 0;



  while (a <= b) {

    c = c + a; //add c to itself

    a += 1; // increment a by one each time

  }



  return c;

}



sumAll([10, 5]);

MY QUESTION(S)

1. Is there a more efficient way to do this?


2. How would I use Math.max() and Math.min() for an array?