Does anyone have a better idea of how I should do this?

Actually there is no need for you to have TWO different Controller actions, instead you can have only ONE. And this action is going to return a view which you want to display.

One way to make a POST is to use HTML.BeginForm() and pass Controller and Action names along with FormMethod.POST to BeginForm(). Inside the BeginForm, you can have a HTML Input Button of type Submit to make the POST call to Controller action.

Also if you want to differentiate the invocation of this controller action, I would suggest you something like this -

First construct you model like this with Type variable through which you can differentiate the operation you need to perform on data -

public class Details

{

    public string easting { get; set; }

    public string northing { get; set; }

    public string type { get; set; }

}

And let your controller action be defined like this -

[HttpPost]

public ActionResult Map(Details details)

And you can have your view define a HiddenField like this -

@model Namespace.Details



@{

    ViewBag.Title = Title;

}



<div id=uploadCourseList>

    @using (Html.BeginForm(Action, Controller, FormMethod.Post))

    {

        @* Other properties of Model *@

        @Html.HiddenFor(m => m.type)

        <input type=submit>

    }

</div>

Now on the view set the type, so that you can differentiate the post operation and perform necessary calculations on your data and return the view.