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rated 0 times [  71] [ 4]  / answers: 1 / hits: 63477  / 10 Years ago, tue, may 27, 2014, 12:00:00

I have tried to convert a JS object into JSON.



JSON.stringify({a:1, toJSON: function(){}})


Native JSON stringify is not working as expected. JSON stringify executes toJSON function in JS object internally. I have overwritten native code as follows,



// Adding try catch for non JSON support browsers.
try{
_jsonStringify = JSON.stringify;
JSON.stringify = function(object){
var fnCopy = object.toJSON;
object.toJSON = undefined;
var result = _jsonStringify(object);
object.toJSON = fnCopy;
return result;
};
}catch(e){}


It is working fine. is there any other better way to do this?. is there any specific reason in native code execute toJSON function in input object?


More From » json

 Answers
1

This is because JSON.stringify will return the return value of the toJSON function if it exists (Source).



For example:



JSON.stringify({a:1, toJSON: function(){ return a; }});


Will return:



a


This behaviour is described on MDN. The reason for this is so that you can customize the behaviour of the serialization. For example, say I only want to serialize the IDs of the Animal class in this example. I could do the following:



var Animal = function(id, name) {
this.AnimalID = id;
this.Name = name;
};

Animal.prototype.toJSON = function() {
return this.AnimalID;
};

var animals = [];

animals.push(new Animal(1, Giraffe));
animals.push(new Animal(2, Kangaroo));

JSON.stringify(animals); // Outputs [1,2]


If you do not want this behaviour then your current method works well; however, I would recommend not overwriting the behaviour of JSON.stringify, but rather name your method something else. An external library might be using the toJSON function in an object and it could lead to unexpected results.


[#70834] Saturday, May 24, 2014, 10 Years  [reply] [flag answer]
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turnerf

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