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rated 0 times [  39] [ 2]  / answers: 1 / hits: 16963  / 11 Years ago, wed, august 7, 2013, 12:00:00

I just started getting involved in web visualizations, so I'm totally novice. My goal is to display a family tree where a root node would have both multiple parents and children. While looking for a solution I found this example: http://bl.ocks.org/jdarling/2503502
It's great because it seems to have the feature I need. However, I would like to alter the orientation (top-to-bottom). I tried to do so using this example: http://bl.ocks.org/mbostock/3184089 but failed.



My code:



var tree = d3.layout.tree()
.size([height, width]);

var diagonal = d3.svg.diagonal()
.projection(function(d) {
return [d.x, d.y];
});

var elbow = function (d, i){
var source = calcTop(d.source);
var target = calcTop(d.target);
var hx = (target.x-source.x)/2;
if(d.isRight)
hx = -hx;
return M + source.x + , + source.y
+ H + (source.x+hx)
+ V + target.y + H + target.x;
};

var connector = elbow;

var calcTop = function(d){
var top = d.x;
if(!d.isRight){
top = d.x-halfHeight;
top = halfHeight - top;
}
return {x : top, y : d.y};
};

var vis = d3.select(#chart)
.append(svg)
.attr(height, height + margin.top + margin.bottom)
.attr(width, width + margin.right + margin.left)
.append(g)
.attr(transform, translate( + margin.left + , + margin.top + ));

d3.json(tree.json, function(json) {
root = json;
root.x0 = height / 2;
root.y0 = width / 2;
var t1 = d3.layout.tree()
.size([halfHeight, width])
.children(function(d){
return d.winners;
});
var t2 = d3.layout.tree()
.size([halfHeight, width])
.children(function(d){
return d.challengers;
});
t1.nodes(root);
t2.nodes(root);

var rebuildChildren = function(node){
node.children = getChildren(node);
if(node.children)
node.children.forEach(rebuildChildren);
}
rebuildChildren(root);
root.isRight = false;
update(root);
});

var toArray = function(item, arr){
arr = arr || [];
var i = 0, l = item.children?item.children.length:0;
arr.push(item);
for(; i < l; i++){
toArray(item.children[i], arr);
}
return arr;
};

function update(source) {
// Compute the new tree layout.
var nodes = toArray(source);

// Normalize for fixed-depth.
nodes.forEach(function(d) { d.x = d.depth * 180 + halfHeight; });

// Update the nodes…
var node = vis.selectAll(g.node)
.data(nodes, function(d) { return d.id || (d.id = ++i); });

// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append(g)
.attr(class, node)
.attr(transform, function(d) {
return translate( + source.x0 + , + source.y0 + );
})
.on(click, click);

nodeEnter.append(circle)
.attr(r, 1e-6)
.style(fill, function(d) {
return d._children ? lightsteelblue : #fff;
});

nodeEnter.append(text)
.attr(dy, function(d) { return d.isRight?14:-8;})
.attr(text-anchor, middle)
.text(function(d) { return d.name; })
.style(fill-opacity, 1e-6);

// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr(transform, function(d) {
p = calcTop(d);
return translate( + p.x + , + p.y + );
});

nodeUpdate.select(circle)
.attr(r, 4.5)
.style(fill, function(d) {
return d._children ? lightsteelblue : #fff;
});

nodeUpdate.select(text)
.style(fill-opacity, 1);

// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr(transform, function(d) {
p = calcTop(d.parent||source);
return translate( + p.x + , + p.y + );
})
.remove();

nodeExit.select(circle)
.attr(r, 1e-6);

nodeExit.select(text)
.style(fill-opacity, 1e-6);

// Update the links...
var link = vis.selectAll(path.link)
.data(tree.links(nodes), function(d) { return d.target.id; });

// Enter any new links at the parent's previous position.
link.enter().insert(path, g)
.attr(class, link)
.attr(d, function(d) {
var o = {x: source.x0, y: source.y0};
return connector({source: o, target: o});
});

// Transition links to their new position.
link.transition()
.duration(duration)
.attr(d, connector);

// Transition exiting nodes to the parent's new position.
link.exit()
.transition()
.duration(duration)
.attr(d, function(d) {
var o = calcTop(d.source||source);
if(d.source.isRight)
o.x -= halfHeight - (d.target.x - d.source.x);
else
o.x += halfHeight - (d.target.x - d.source.x);
return connector({source: o, target: o});
})
.remove();

// Stash the old positions for transition.
nodes.forEach(function(d) {
var p = calcTop(d);
d.x0 = p.x;
d.y0 = p.y;
});

// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(source);


}
}



Would really appreciate the help!


More From » svg

 Answers
24

The example you're looking at is actually already flipped - this might be causing you some confusion. Trees in D3 are naturally top-down trees, and the code does a lot of x-y flipping to make the tree sideways.



Changing



  var nodeUpdate = node.transition()
.duration(duration)
.attr(transform, function(d) { p = calcLeft(d); return translate( + p.y + , + p.x + ); })
;


to



  var nodeUpdate = node.transition()
.duration(duration)
.attr(transform, function(d) { p = calcLeft(d); return translate( + p.x + , + p.y + ); })
;


will get the nodes displaying in the right position. Doing a similar change with any instance of swapped x-y coordinates inside update() fixes most of the positioning issues. One last thing is the elbow function/variable/whatever you want to call it, where



  return M + source.y + , + source.x
+ H + (source.y+hy)
+ V + target.x + H + target.y;


should be changed to



  return M + source.x + , + source.y
+ V + (source.y+hy)
+ H + target.x + V + target.y;


This changes the connector shape from horizontal vertical horizontal to vertical horizontal vertical. Note that this is a raw SVG line, not d3 at all. The changes I made (plus swapping width and height, and changing the AJAX JSON request to hardcoding the data - AJAX is hard to get working in fiddle) are all at http://jsfiddle.net/Zj3th/2/.



If you have no experience with d3 and SVG, I would definitely take a look and fully understand a simple example like http://blog.pixelingene.com/2011/07/building-a-tree-diagram-in-d3-js/ before you go further in modifying the code.


[#76484] Tuesday, August 6, 2013, 11 Years  [reply] [flag answer]
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jameson

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