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rated 0 times [  74] [ 5]  / answers: 1 / hits: 116486  / 11 Years ago, mon, june 17, 2013, 12:00:00

How can I use ranges in a switch case statement using JavaScript? So, instead of writing code for each and every single possibility, I'd like to group them in ranges, For example:



switch(myInterval){
case 0-2:
//doStuffWithFirstRange();
break;

case 3-6:
//doStuffWithSecondRange();
break;

case 6-7:
//doStuffWithThirdRange();
break;

default:
//doStuffWithAllOthers();
}

More From » switch-statement

 Answers
41

You have at least four options:



1. List each case



As shown by LightStyle, you can list each case explicitly:



switch(myInterval){

case 0:
case 1:
case 2:
doStuffWithFirstRange();
break;

case 3:
case 4:
case 5:
doStuffWithSecondRange();
break;

case 6:
case 7:
doStuffWithThirdRange();
break;

default:
doStuffWithAllOthers();
}


2. Use if / else if / else



If the ranges are large, that gets unwieldy, so you'd want to do ranges. Note that with if...else if...else if, you don't get to the later ones if an earlier one matches, so you only have to specify the upper bound each time. I'll include the lower bound in /*...*/ for clarity, but normally you would leave it off to avoid introducing a maintenance issue (if you include both boundaries, it's easy to change one and forget to change the other):



if (myInterval < 0) {
// I'm guessing this is an error
}
else if (/* myInterval >= 0 && */ myInterval <= 2){
doStuffWithFirstRange();
}
else if (/* myInterval >= 3 && */ myInterval <= 5) {
doStuffWithSecondRange();
}
else if (/* myInterval >= 6 && */ myInterval <= 7) {
doStuffWithThirdRange();
}
else {
doStuffWithAllOthers();
}


3. Use case with expressions:



JavaScript is unusual in that you can use expressions in the case statement, so we can write the if...else if...else if sequence above as a switch statement:



switch (true){

case myInterval < 0:
// I'm guessing this is an error
break;
case /* myInterval >= 0 && */ myInterval <= 2:
doStuffWithFirstRange();
break;

case /* myInterval >= 3 && */ myInterval <= 5:
doStuffWithSecondRange();
break;

case /* myInterval >= 6 && */ myInterval <= 7:
doStuffWithThirdRange();
break;

default:
doStuffWithAllOthers();
}


I'm not advocating that, but it is an option in JavaScript, and there are times it's useful. The case statements are checked in order against the value you give in the switch. (And again, lower bounds could be omitted in many cases because they would have matched earlier.) Even though the cases are processed in source-code order, the default can appear anywhere (not just at the end) and is only processed if either no cases matched or a case matched and fell through to the default (didn't have a break; it's rare you want to do that, but it happens).



4. Use a dispatch map



If your functions all take the same arguments (and that could be no arguments, or just the same ones), another approach is a dispatch map:



In some setup code:



var dispatcher = {
0: doStuffWithFirstRange,
1: doStuffWithFirstRange,
2: doStuffWithFirstRange,

3: doStuffWithSecondRange,
4: doStuffWithSecondRange,
5: doStuffWithSecondRange,

6: doStuffWithThirdRange,
7: doStuffWithThirdRange
};


Then instead of the switch:



(dispatcher[myInterval] || doStuffWithAllOthers)();


That works by looking up the function to call on the dispatcher map, defaulting to doStuffWithAllOthers if there's no entry for that specific myInterval value using the curiously-powerful || operator, and then calling it.



You can break that into two lines to make it a bit clearer:



var f = dispatcher[myInterval] || doStuffWithAllOthers;
f();


I've used an object for maximum flexibility. You could define dispatcher like this with your specific example:



var dispatcher = [
/* 0-2 */
doStuffWithFirstRange,
doStuffWithFirstRange,
doStuffWithFirstRange,

/* 3-5 */
doStuffWithSecondRange,
doStuffWithSecondRange,
doStuffWithSecondRange,

/* 6-7 */
doStuffWithThirdRange,
doStuffWithThirdRange
];


...but if the values aren't contiguous numbers, it's much clearer to use an object instead.


[#77589] Friday, June 14, 2013, 11 Years  [reply] [flag answer]
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emilianoc

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