Question

29

jquery .replace(/./g, ) do not work for me but others

rated 0 times [ 32] [ 3] / answers: 1 / hits: 51947 / 11 Years ago, thu, june 6, 2013, 12:00:00

I found this snippet somewhere and it works like a charm:

var n = parseInt(e.find(span.favNum).text().replace(/./g, )) + 1;

If I do it in a similar way it doesn't work anymore.

I do the following:

<div id =test>6.987</div>

var test = $(#test);

var r = test.text().replace(/./g, );

console.log(wrong , r);

I know that I can replace it also like this:

var r = test.text().replace(., );

This works.

I would like to understand why the stolen snippet is working.
Any idea?

http://jsfiddle.net/nJZMf/3/

The original script is found here: http://wp-svbtle.themeskult.com/

You will find the snippet by viewing the source of index.html and searching for .replace.

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answered 11 Years ago trinityr · Accepted Answer

The reason that the code in the page you linked to works, where yours doesn't, is that it's not the same regular expression. Here's what I found in that page (and similar code in several places)

r = n.text().replace( /,/g,  )

where r is a jQuery object.

Note that the regular expression has a , inside the //, not a . like the code you had trouble with.

Comma is not a special character in regular expressions, so it needs no special treatment. Period has a special meaning. As the other answers pointed out, it matches all characters, and you need to prefix it with if you want to match . only.

Also note that .replace() is not jQuery code, it's JavaScript.

jQuery's .text() method returns a JavaScript String value. So anything you do with that string - such as the .replace() call - is actually a JavaScript String method.

The distinction is important when you want to research a problem: a search for javascript string replace will get you better information than jquery replace.