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/ answers: 1 / hits: 15981
/ 11 Years ago, mon, may 13, 2013, 12:00:00
What I have now is
function setMenuCurrentTo(variable)
{
document.getElementById(game_ + variable).style.display = block;
var elems = document.getElementsByClassName(current_nav);
for (var i=elems.length; i--;) {
elems[i].style.display = none;
elems[i].className = 'none';
}
document.getElementById(game_ + variable).className=current_nav;
}
}
So when I click a tag with a specific element(variable) it adds a content and hides another one. But there is a bug that when I click twice in the same button, the content dissapears and I don't have anymore content.
So I tried this code:
function setMenuCurrentTo(variable)
{
document.getElementById(game_ + variable).style.display = block;
if (getElementById(game_ + variable).hasClass(current_nav)) {
}
else {
var elems = document.getElementsByClassName(current_nav);
for (var i=elems.length; i--;) {
elems[i].style.display = none;
elems[i].className = 'none';
}
document.getElementById(game_ + variable).className=current_nav;
}
The
if (getElementById(game_ + variable).hasClass(current_nav)) {} else {
Make the code don't work, the content appears but no other hides. What is the problem in my code? Thank you, I'm very new at JavaScript, I got yesterday help for the original code. Thank you again.
EDIT:
I got the correct answer: from wroniasty
function setMenuCurrentTo(variable)
{
document.getElementById(game_ + variable).style.display = block;
if (jQuery('#game_' + variable).hasClass('current_nav')) {
}
else {
var elems = document.getElementsByClassName(current_nav);
for (var i=elems.length; i--;) {
elems[i].style.display = none;
elems[i].className = 'none';
}
document.getElementById(game_ + variable).className=current_nav;
}
}
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