Question

151

Javascript password validation

rated 0 times [ 156] [ 5] / answers: 1 / hits: 37837 / 11 Years ago, mon, april 22, 2013, 12:00:00

Can anyone suggest an easy password validation using javascript. I need it to be at least 4 characters long and contain min 1 letter and 1 number.

This is a school project so its really only a simple validation needed to make sure they are entering in the required characters.

I am using

<textarea id=special_info name=address onfocus=this.value='' rows=5 cols=40 >Please enter your address...

            </textarea>

            <div id=maxcar>(Maximum characters: 200)

            </div>

My javascript is in this format

function validate_form(){



valid=true;



var letters=/^[a-zA-Z]+$/;

var numbers=/^[0-9]+$/;

var email=document.order_form.user_email.value;

var invalid = [];



if (document.order_form.first_name.value.search(letters)==-1){

invalid.push(*First Name)

}   



if (document.order_form.surname.value.search(letters)==-1){

invalid.push(*Surname Name)

}



if (email.indexOf(@)<1 || email.lastIndexOf(.)<email.indexOf(@)+2 

|| email.lastIndexOf(.)+2>=email.length){

invalid.push(*Email)

}



if (invalid.length != 0)

{alert(Please provide response: n + invalid.join(n) ); 

    valid = false;

    invalid = [];}





return valid;}

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jamir

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answered 11 Years ago oliverkarle · Accepted Answer

Try this:

// returns true if the form was valid; false otherwise.



function validateForm() {



    var allLetters = /^[a-zA-Z]+$/;

    var letter = /[a-zA-Z]/;

    var number = /[0-9]/;



    var firstName = document.order_form.first_name.value;

    var surname = document.order_form.surname.value;

    var email = document.order_form.user_email.value;

    var password = document.order_form.password.value;



    var invalid = [];



    if (!allLetters.test(firstName)) {

        invalid.push(*First Name);

    }



    if (!allLetters.test(surname)) {

        invalid.push(*Surname Name);

    }



    if (email.indexOf(@) < 1 || email.lastIndexOf(.) < email.indexOf(@) + 2 || email.lastIndexOf(.) + 2 >= email.length) {

        invalid.push(*Email);

    }



    if (password.length < 4 || !letter.test(password) || !number.test(password)) {

        invalid.push(*Password);

    }



    if (invalid.length != 0) {

        alert(Please provide response: n + invalid.join(n));

        return false;

    }



    return true;

}

Give it a good read, run it, and ask questions if something is unclear.

Notice the use of RegExp.test instead of String.search.