Question

189

Push is not a function JavaScript error

rated 0 times [ 196] [ 7] / answers: 1 / hits: 49872 / 12 Years ago, thu, january 10, 2013, 12:00:00

In the below code, I am getting push is not a function error. Can anyone please let me know what I am doing wrong here? I am trying to create 2D array in Javascript.

var myArray = new Array(4);

myArray = [0,0,0,0];



for (var i=0; i<myArray.length; i++) {

    myArray[i].push(ID);

    myArray[i] = new Array(1);

    for (var j=0; j<myArray[i].length; i++) {

        myArray[i][j].push(Array[j]);

    }

}

Firebug is pointing me to:

myArray[i].push(ID);

For this line I am getting TypeError: myArray[i].push is not a function

Final array it should look like is:

[ID,SomeValue1],

[ID,SomeValue2],

[ID,SomeValue3]

And I cannot hard code, I need to create this dynamically based on data from DB

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answered 12 Years ago brandt · Accepted Answer

This will create your example.

var myArray = new Array(4);

for (var i = 0; i < myArray.length; i++) {

  myArray[i] = [ID, SomeValue + (i+1)];

}

But if you need to set data from a database, how is that being set in the Javascript? if it's in a different array you could do the following:

var dbArray = [SomeValue1, SomeValue2, SomeValue3];



var myArray = new Array(dbArray.length);

for (var i = 0; i < myArray.length; i++) {

  myArray[i] = [ID, dbArray[i]];

}