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/ answers: 1 / hits: 114179
/ 12 Years ago, tue, october 2, 2012, 12:00:00
I want to achieve something like this:
class TestClass {
someMethod(stringParameter: string): void {
alert("Variant #1: stringParameter = " + stringParameter);
}
someMethod(numberParameter: number, stringParameter: string): void {
alert("Variant #2: numberParameter = " + numberParameter + ", stringParameter = " + stringParameter);
}
}
var testClass = new TestClass();
testClass.someMethod("string for v#1");
testClass.someMethod(12345, "string for v#2");
Here is an example of what I don't want to do (I really hate that part of overloading hack in JS):
class TestClass {
private someMethod_Overload_string(stringParameter: string): void {
// A lot of code could be here... I don't want to mix it with switch or if statement in general function
alert("Variant #1: stringParameter = " + stringParameter);
}
private someMethod_Overload_number_string(numberParameter: number, stringParameter: string): void {
alert("Variant #2: numberParameter = " + numberParameter + ", stringParameter = " + stringParameter);
}
private someMethod_Overload_string_number(stringParameter: string, numberParameter: number): void {
alert("Variant #3: stringParameter = " + stringParameter + ", numberParameter = " + numberParameter);
}
public someMethod(stringParameter: string): void;
public someMethod(numberParameter: number, stringParameter: string): void;
public someMethod(stringParameter: string, numberParameter: number): void;
public someMethod(): void {
switch (arguments.length) {
case 1:
if(typeof arguments[0] == "string") {
this.someMethod_Overload_string(arguments[0]);
return;
}
return; // Unreachable area for this case, unnecessary return statement
case 2:
if ((typeof arguments[0] == "number") &&
(typeof arguments[1] == "string")) {
this.someMethod_Overload_number_string(arguments[0], arguments[1]);
}
else if ((typeof arguments[0] == "string") &&
(typeof arguments[1] == "number")) {
this.someMethod_Overload_string_number(arguments[0], arguments[1]);
}
return; // Unreachable area for this case, unnecessary return statement
}
}
}
var testClass = new TestClass();
testClass.someMethod("string for v#1");
testClass.someMethod(12345, "string for v#2");
testClass.someMethod("string for v#3", 54321);
How to do method overloading in TypeScript language?
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