Question

59

rated 0 times [ 65] [ 6] / answers: 1 / hits: 153801 / 12 Years ago, tue, may 1, 2012, 12:00:00

Those two regex act the same way:

var str = 43gf\..--.65;



console.log(str.replace(/[^d.-]/g, ));

console.log(str.replace(/[^d.-]/g, ));

In the first regex I don't escape the dot(.) while in the second regex I do(.).

What are the differences? Why is the result the same?

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answered 12 Years ago brynneg · Accepted Answer

Because the dot is inside character class (square brackets []).

Take a look at http://www.regular-expressions.info/reference.html, it says (under char class section):

Any character except ^-] add that character to the possible matches
for the character class.